What is the asymptotes of f(x)=((x^2+1))/(7x-4x^2) ?

The asymptotes of f(x)=((x^2+1))/(7x-4x^2) is Vertical: x=0,x= 7/4 ,Horizontal: y=-1/4

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asymptotes of f(x)=((x^2+1))/(7x-4x^2)

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{7 x - 4 x ^{2}}

Vertical : x = 0, x = \frac{7}{4}, Horizontal : y = - \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{7 x - 4 x ^{2}} : x = 0, x = \frac{7}{4}

Horizontal Asymptotes of

\frac{x ^{2} + 1}{7 x - 4 x ^{2}} : y = - \frac{1}{4}

Slant Asymptotes of

\frac{x ^{2} + 1}{7 x - 4 x ^{2}} :

None

Vertical : x = 0, x = \frac{7}{4}, Horizontal : y = - \frac{1}{4}

f (x) = \frac{1}{4} x^{3} - 5

f (x) = - 2 cos (3 x)

lo g_{10} (x + 4)

- 4 sin (x + \frac{π}{3})

(m, p), (0, 0)

What is the asymptotes of f(x)=((x^2+1))/(7x-4x^2) ?
The asymptotes of f(x)=((x^2+1))/(7x-4x^2) is Vertical: x=0,x= 7/4 ,Horizontal: y=-1/4