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midpoint (4,-1),(-1,-4)midpoint range of f(x)= 2/(x^2)range asymptotes of f(x)=(x^2)/((x-1)^2)asymptotes domain of f(x)= 1/(sqrt(3-2x-x^2))domain range of f(x)=-2range
Frequently Asked Questions (FAQ)
What is the inverse of f(x)=-(0.009(x-220)^2-220) ?
The inverse of f(x)=-(0.009(x-220)^2-220) is sqrt((-x+220)/(0.009))+220,-sqrt((-x+220)/(0.009))+220