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Popular >

inverse of h(x)= 1/(x-1)

Solution

inverse

h (x) = \frac{1}{x - 1}

Solution

\frac{1}{x} + 1

Solution steps

y = \frac{1}{x - 1}

Replace

x

with

y

x = \frac{1}{y - 1}

Solve for

y, x = \frac{1}{y - 1}

\frac{1}{x} + 1

Popular Examples

extreme f(x)=-4x^3+6x^2-5 extreme points

f (x) = - 4 x^{3} + 6 x^{2} - 5

asymptotes of f(x)=2*3^{x-4}asymptotes

f (x) = 2 \cdot 3^{x - 4}

periodicity of f(x)= 5/3 sin(-(2pi)/3 x)periodicity

f (x) = \frac{5}{3} sin (- \frac{2 π}{3} x)

perpendicular y=8x-3,(6,2)perpendicular

y = 8 x - 3, (6, 2)

domain of f(x)=(x/(x+7))/(x/(x+7)+7)domain

f (x) = \frac{\frac{x}{x + 7}}{\frac{x}{x + 7} + 7}

Frequently Asked Questions (FAQ)

What is the inverse of h(x)= 1/(x-1) ?
The inverse of h(x)= 1/(x-1) is 1/x+1