What is the critical f(x)=2x^3+3x^2-72x ?

The critical f(x)=2x^3+3x^2-72x is x=-4,x=3

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critical f(x)=2x^3+3x^2-72x

critical points

f (x) = 2 x^{3} + 3 x^{2} - 72 x

x = - 4, x = 3

Solution steps

2 x^{3} + 3 x^{2} - 72 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 3

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} + 3 x^{2} - 72 x : - \infty < x < \infty

All critical points are in domain

x = - 4, x = 3

2 x^{3} + 13 x^{2} + 17 x - 12

(4, 4), (- 2, 7)

f (x) = x^{2} + y^{2} = 9

f (x) = \frac{x + 6}{x - 2}

What is the critical f(x)=2x^3+3x^2-72x ?
The critical f(x)=2x^3+3x^2-72x is x=-4,x=3