What is the extreme sin^2(x),0<= x<= pi ?

The extreme sin^2(x),0<= x<= pi is Minimum(0,0),Maximum(pi/2 ,1),Minimum(pi,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme sin^2(x),0<= x<= pi

extreme points

sin^{2} (x), 0 \leq x \leq π

Minimum (0, 0), Maximum (\frac{π}{2}, 1), Minimum (π, 0)

Solution steps

Find the critical points:

x = 0, x = \frac{π}{2}, x = π

Domain of

sin^{2} (x), 0 \leq x \leq π : 0 \leq x \leq π

Find intervals:

Increasing

: 0 < x < \frac{π}{2},

Decreasing

: \frac{π}{2} < x < π

Plug the extreme point

x = 0

into

sin^{2} (x) \Rightarrow y = 0

Minimum (0, 0)

Plug the extreme point

x = \frac{π}{2}

into

sin^{2} (x) \Rightarrow y = 1

Maximum (\frac{π}{2}, 1)

Plug the extreme point

x = π

into

sin^{2} (x) \Rightarrow y = 0

Minimum (π, 0)

Minimum (0, 0), Maximum (\frac{π}{2}, 1), Minimum (π, 0)

f (x) = 3

f (x) = x^{2} - 11 x + 13

f (x) = t^{2} - 7 t + 10

f (x) = \frac{4 x + 7}{x + 4}

- (x + 1)^{2} - 4

What is the extreme sin^2(x),0<= x<= pi ?
The extreme sin^2(x),0<= x<= pi is Minimum(0,0),Maximum(pi/2 ,1),Minimum(pi,0)