What is the inverse of f(x)=2x^2-5x+1 ?

The inverse of f(x)=2x^2-5x+1 is (5+sqrt(8x+17))/4 ,(5-sqrt(8x+17))/4

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inverse of f(x)=2x^2-5x+1

inverse

f (x) = 2 x^{2} - 5 x + 1

\frac{5 + 8 x + 17}{4}, \frac{5 - 8 x + 17}{4}

Solution steps

y = 2 x^{2} - 5 x + 1

Replace

x

with

y

x = 2 y^{2} - 5 y + 1

Solve for

y, x = 2 y^{2} - 5 y + 1

\frac{5 + 8 x + 17}{4}, \frac{5 - 8 x + 17}{4}

\frac{3 x}{x - 1}

y = \frac{x ^{2} - 4}{x ^{2} + 4}

g (x) = 5 x^{2} + 2

f (x) = \frac{4 t}{3 t - 8}

f (x) = 7 x

What is the inverse of f(x)=2x^2-5x+1 ?
The inverse of f(x)=2x^2-5x+1 is (5+sqrt(8x+17))/4 ,(5-sqrt(8x+17))/4