What is the domain of f(x)=sqrt(x^2-2x-3) ?

The domain of f(x)=sqrt(x^2-2x-3) is x = 3

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domain of f(x)=sqrt(x^2-2x-3)

domain

f (x) = x^{2} - 2 x - 3

x \leq - 1 or x \geq 3

Interval Notation

(- \infty, - 1] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 3

The function domain

x \leq - 1 or x \geq 3

(24, - 1), (29, 2)

y = \frac{2}{5} x - 4

f (x) = (\frac{3}{x ^{2} - 1}) + 1

y = sec (x)

f (x) = \frac{x}{( ln ( x ) ) ^{2}}

What is the domain of f(x)=sqrt(x^2-2x-3) ?
The domain of f(x)=sqrt(x^2-2x-3) is x<=-1\lor x>= 3