What is the domain of f(x)=(3/(x^2-1))+1 ?

The domain of f(x)=(3/(x^2-1))+1 is x 1

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domain of f(x)=(3/(x^2-1))+1

domain

f (x) = (\frac{3}{x ^{2} - 1}) + 1

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

y = sec (x)

f (x) = \frac{x}{( ln ( x ) ) ^{2}}

f (x) = \frac{1}{x + 6}

(3.3) (- 3.1)

\frac{x ^{2} - 3 x - 4}{1 + 4 x + 4 x ^{2}}

What is the domain of f(x)=(3/(x^2-1))+1 ?
The domain of f(x)=(3/(x^2-1))+1 is x<-1\lor-1<x<1\lor x>1