What is the asymptotes of (x^2-3x-4)/(1+4x+4x^2) ?

The asymptotes of (x^2-3x-4)/(1+4x+4x^2) is Vertical: x=-1/2 ,Horizontal: y= 1/4

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asymptotes of (x^2-3x-4)/(1+4x+4x^2)

asymptotes

\frac{x ^{2} - 3 x - 4}{1 + 4 x + 4 x ^{2}}

Vertical : x = - \frac{1}{2}, Horizontal : y = \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x - 4}{1 + 4 x + 4 x ^{2}} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{x ^{2} - 3 x - 4}{1 + 4 x + 4 x ^{2}} : y = \frac{1}{4}

Slant Asymptotes of

\frac{x ^{2} - 3 x - 4}{1 + 4 x + 4 x ^{2}} :

None

Vertical : x = - \frac{1}{2}, Horizontal : y = \frac{1}{4}

f (x) = \frac{2}{x} + 2 x

\frac{8 x}{5} - 2 y = - 8

m = - \frac{1}{3}, (\frac{7}{3}, \frac{2}{3})

y = 1 + lo g_{3} (x)

y = 4 x + 6

What is the asymptotes of (x^2-3x-4)/(1+4x+4x^2) ?
The asymptotes of (x^2-3x-4)/(1+4x+4x^2) is Vertical: x=-1/2 ,Horizontal: y= 1/4