What is the line m=-1/3 ,(7/3 , 2/3) ?

The line m=-1/3 ,(7/3 , 2/3) is y=-1/3 x+13/9

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line m=-1/3 ,(7/3 , 2/3)

line

m = - \frac{1}{3}, (\frac{7}{3}, \frac{2}{3})

y = - \frac{1}{3} x + \frac{13}{9}

Solution steps

Compute the line equation

y = mx + b

for slope m=

- \frac{1}{3}

and passing through

(\frac{7}{3}, \frac{2}{3})

Compute the

y

intercept:

b = \frac{13}{9}

Construct the line equation

y = mx + b

where

m = - \frac{1}{3}

and

b = \frac{13}{9}

y = - \frac{1}{3} x + \frac{13}{9}

y = 1 + lo g_{3} (x)

y = 4 x + 6

\frac{4 x - 3}{6 - 5 x}

\frac{( x - 1 ) ( x + 3 )}{x ^{2} - 4}

4 x - 6 y = - 8

What is the line m=-1/3 ,(7/3 , 2/3) ?
The line m=-1/3 ,(7/3 , 2/3) is y=-1/3 x+13/9