What is the range of f(x)=(8x)/(x+5) ?

The range of f(x)=(8x)/(x+5) is f(x) 8

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range of f(x)=(8x)/(x+5)

range

f (x) = \frac{8 x}{x + 5}

f (x) < 8 or f (x) > 8

Interval Notation

(- \infty, 8) \cup (8, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{8 x}{x + 5}

Inverse of

\frac{8 x}{x + 5} : - \frac{5 x}{x - 8}

- \frac{5 x}{x - 8}

Find the domain of each inverse function

Domain of

- \frac{5 x}{x - 8} : x < 8 or x > 8

Combine the intervals

f (x) < 8 or f (x) > 8

f (x) = arctan (\frac{x}{2 - x})

f (x) = 3 lo g_{5} (x + 1) - 2

\frac{x ^{2} + 3 x - 2}{x ^{2} + 2 x - 3}

x^{3} - 6 x^{2}

f (x) = 4 x^{2} + 7

What is the range of f(x)=(8x)/(x+5) ?
The range of f(x)=(8x)/(x+5) is f(x)<8\lor f(x)>8