What is the extreme 24000x^2+900x-150 ?

The extreme 24000x^2+900x-150 is Minimum(-3/160 ,-2535/16)

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extreme 24000x^2+900x-150

extreme points

24000 x^{2} + 900 x - 150

Minimum (- \frac{3}{160}, - \frac{2535}{16})

Solution steps

f^{'} (x) = 48000 x + 900

Find intervals:

Decreasing

: - \infty < x < - \frac{3}{160},

Increasing

: - \frac{3}{160} < x < \infty

Plug

x = - \frac{3}{160}

into

24000 x^{2} + 900 x - 150 : - \frac{2535}{16}

Minimum (- \frac{3}{160}, - \frac{2535}{16})

\frac{x ^{2} - 16}{x + 4}

\frac{2}{3} x + 2 y = \frac{- 8}{3}, (- 5, 5)

- (x + 4) (x - 4) - x + 1

\frac{x + 1}{x - 1}

(4, 7), (1, 1)

What is the extreme 24000x^2+900x-150 ?
The extreme 24000x^2+900x-150 is Minimum(-3/160 ,-2535/16)