What is the domain of \sqrt[4]{x^2+3x} ?

The domain of \sqrt[4]{x^2+3x} is x = 0

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domain of \sqrt[4]{x^2+3x}

domain

x \leq - 3 or x \geq 0

Interval Notation

(- \infty, - 3] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 0

The function domain

x \leq - 3 or x \geq 0

y = 1

f (x) = \frac{x + 8}{x + 6}

f (x) = \frac{1}{4 x - 20}

f (x) = 10 x - 1

What is the domain of \sqrt[4]{x^2+3x} ?
The domain of \sqrt[4]{x^2+3x} is x<=-3\lor x>= 0