What is the domain of (sqrt(x-3))/(x^2-16) ?

The domain of (sqrt(x-3))/(x^2-16) is 3 4

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domain of (sqrt(x-3))/(x^2-16)

domain

\frac{x - 3}{x ^{2} - 16}

3 \leq x < 4 or x > 4

Interval Notation

[3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

3 \leq x < 4 or x > 4

f (x) = x^{3} - 27 x + 1

6 x - 2 y = 18

f (x) = \frac{1}{x - 4} - 2

f (x) = \frac{10}{4 - x}

f (x) = \frac{24}{x + 3}

What is the domain of (sqrt(x-3))/(x^2-16) ?
The domain of (sqrt(x-3))/(x^2-16) is 3<= x<4\lor x>4