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Popular >

distance (-2,-3),(-10,0)

Solution

distance

(- 2, - 3), (- 10, 0)

Solution

73

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, - 3)

and

(- 10, 0)

is

= (- 10 - (- 2))^{2} + (0 - (- 3))^{2}

Simplify

= 73

Popular Examples

perpendicular y=-2x+8 perpendicular

y = - 2 x + 8

intercepts of f(x)=3x^2-18x+26 intercepts

f (x) = 3 x^{2} - 18 x + 26

parallel Y(x)=-1/3 x+6,(-6,0)parallel

Y (x) = - \frac{1}{3} x + 6, (- 6, 0)

intercepts of f(x)=2x^3-2x^2-7x+3 intercepts

f (x) = 2 x^{3} - 2 x^{2} - 7 x + 3

asymptotes of f(x)=((2x^2))/((x^2+5x+4))asymptotes

f (x) = \frac{( 2 x ^{2} )}{( x ^{2} + 5 x + 4 )}

Frequently Asked Questions (FAQ)

What is the distance (-2,-3),(-10,0) ?
The distance (-2,-3),(-10,0) is square root of 73