What is the domain of f(x)=sqrt(x^2+4x-21) ?

The domain of f(x)=sqrt(x^2+4x-21) is x = 3

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domain of f(x)=sqrt(x^2+4x-21)

domain

f (x) = x^{2} + 4 x - 21

x \leq - 7 or x \geq 3

Interval Notation

(- \infty, - 7] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 7 or x \geq 3

The function domain

x \leq - 7 or x \geq 3

f (x) = \frac{x - 5}{2 x + 4}

f (x) = x^{2}

f (x) = x + 20 - 1

7 \frac{5}{8}

\frac{x ^{2} - 3}{x ^{2} - 7}

What is the domain of f(x)=sqrt(x^2+4x-21) ?
The domain of f(x)=sqrt(x^2+4x-21) is x<=-7\lor x>= 3