What is the domain of f(x)=(x-1)/(x^2+1) ?

The domain of f(x)=(x-1)/(x^2+1) is -infinity <x<infinity

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domain of f(x)=(x-1)/(x^2+1)

domain

f (x) = \frac{x - 1}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x ^{2} - 5 x + 6}{4 x + 4}

f (x) = 1 - 2 x

y = \frac{2 x ^{2} + 10 x + 12}{x ^{2} + 3 x + 2}

f (x) = e^{- 5 t}

3 x - y = 1, (3, 8)

What is the domain of f(x)=(x-1)/(x^2+1) ?
The domain of f(x)=(x-1)/(x^2+1) is -infinity <x<infinity