What is the critical f(x)=x^4-2x^2 ?

The critical f(x)=x^4-2x^2 is x=-1,x=0,x=1

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critical f(x)=x^4-2x^2

critical points

f (x) = x^{4} - 2 x^{2}

x = - 1, x = 0, x = 1

Solution steps

x^{4} - 2 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 2 x^{2} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 1

f (x) = \frac{5 x}{x - 1}

f (x) = x^{2} + x + 1

f (x) = 8 - 2 x^{3}

f (x) = \frac{1}{2 x + 4}

\frac{( e ^{x} )}{1 + 9 e ^{x}}