What is the extreme f(x)=x^{2/3}(x-2) ?

The extreme f(x)=x^{2/3}(x-2) is Maximum(0,0),Minimum(4/5 ,-(6*4^{2/3})/(5*5^{2/3)})

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extreme f(x)=x^{2/3}(x-2)

extreme points

f (x) = x^{\frac{2}{3}} (x - 2)

Maximum (0, 0), Minimum (\frac{4}{5}, - \frac{6 \cdot 4 ^{\frac{2}{3}}}{5 \cdot 5 ^{\frac{2}{3}}})

Solution steps

f^{'} (x) = \frac{5 x - 4}{3 x ^{\frac{1}{3}}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \frac{4}{5},

Increasing

: \frac{4}{5} < x < \infty

Plug

x = 0

into

x^{\frac{2}{3}} (x - 2) : 0

Maximum (0, 0)

Plug

x = \frac{4}{5}

into

x^{\frac{2}{3}} (x - 2) : - \frac{6 \cdot 4 ^{\frac{2}{3}}}{5 \cdot 5 ^{\frac{2}{3}}}

Minimum (\frac{4}{5}, - \frac{6 \cdot 4 ^{\frac{2}{3}}}{5 \cdot 5 ^{\frac{2}{3}}})

Maximum (0, 0), Minimum (\frac{4}{5}, - \frac{6 \cdot 4 ^{\frac{2}{3}}}{5 \cdot 5 ^{\frac{2}{3}}})

f (x) = ∣ x - 1 ∣

f (x) = 1 + x \cdot 1 - x

f (x) = \frac{4 x}{x ^{2} + 25}

91.1

f (x) = (x - 6)^{2} + 8

What is the extreme f(x)=x^{2/3}(x-2) ?
The extreme f(x)=x^{2/3}(x-2) is Maximum(0,0),Minimum(4/5 ,-(6*4^{2/3})/(5*5^{2/3)})