What is the domain of f(x)=(sqrt(x^3-8))/(x-4) ?

The domain of f(x)=(sqrt(x^3-8))/(x-4) is 2 4

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domain of f(x)=(sqrt(x^3-8))/(x-4)

domain

f (x) = \frac{x ^{3} - 8}{x - 4}

2 \leq x < 4 or x > 4

Interval Notation

[2, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

2 \leq x < 4 or x > 4

f (x) = 3 (y + 4)^{2}

f (x) = \frac{( x - 2 )}{( x + 3 )}

g (x) = 7 - x

(11 - t)^{6}

f (x) = x - \frac{4}{x}

What is the domain of f(x)=(sqrt(x^3-8))/(x-4) ?
The domain of f(x)=(sqrt(x^3-8))/(x-4) is 2<= x<4\lor x>4