What is the range of f(x)=2^{x+1}-3 ?

The range of f(x)=2^{x+1}-3 is f(x)>-3

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range of f(x)=2^{x+1}-3

range

f (x) = 2^{x + 1} - 3

f (x) > - 3

Interval Notation

(- 3, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = - 3

f (x) > - 3

\frac{3}{5}

f (x) = 2 (3)^{x}

(- \frac{5}{2}, \frac{3}{2}), (- \frac{11}{2}, - \frac{15}{2})

f (x) = \frac{x ^{2} + 8 x - 4}{x - 2}

\frac{x - 3}{x + 3}