What is the inverse of f(x)=x^2+2x+1 ?

The inverse of f(x)=x^2+2x+1 is -1+sqrt(x),-sqrt(x)-1

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inverse of f(x)=x^2+2x+1

inverse

f (x) = x^{2} + 2 x + 1

- 1 + x, - x - 1

Solution steps

y = x^{2} + 2 x + 1

Replace

x

with

y

x = y^{2} + 2 y + 1

Solve for

y, x = y^{2} + 2 y + 1

- 1 + x, - x - 1

f (x) = - 4 x - 12

y = - \frac{1}{4} x + 3

f (x) = - x^{3} + 3 x^{2} - 3

f (x) = x^{2} + 3, x \geq 0

What is the inverse of f(x)=x^2+2x+1 ?
The inverse of f(x)=x^2+2x+1 is -1+sqrt(x),-sqrt(x)-1