What is the range of f(x)=sqrt(x)+6 ?

The range of f(x)=sqrt(x)+6 is f(x)>= 6

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range of f(x)=sqrt(x)+6

range

f (x) = x + 6

f (x) \geq 6

Interval Notation

[6, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 6

f (x) \geq 6

6 x + 3 y = - 6

f (x) = \frac{1 + 4 x}{2 x - 1}

(10.3) (4.7)

12 x^{2} - 204 x + 594

y = 0.25 x - 7, (- 6, 8)