What is the inverse of f(x)= 1/3 x^3-5 ?

The inverse of f(x)= 1/3 x^3-5 is cube root of 3x+15

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inverse of f(x)= 1/3 x^3-5

inverse

f (x) = \frac{1}{3} x^{3} - 5

Solution steps

y = \frac{1}{3} x^{3} - 5

Replace

x

with

y

x = \frac{1}{3} y^{3} - 5

Solve for

y, x = \frac{1}{3} y^{3} - 5

y = \frac{1}{3} x + 15

f (x) = (5 - x + 2)^{4} + 3

f (x) = \frac{2 x ^{2} + 3}{x ^{3} + 2}

f (x) = \frac{4}{3} (x - 1)^{3} + 6

What is the inverse of f(x)= 1/3 x^3-5 ?
The inverse of f(x)= 1/3 x^3-5 is cube root of 3x+15