What is the extreme f(x)=x^3-12x^2-27x+4 ?

The extreme f(x)=x^3-12x^2-27x+4 is Maximum(-1,18),Minimum(9,-482)

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extreme f(x)=x^3-12x^2-27x+4

extreme points

f (x) = x^{3} - 12 x^{2} - 27 x + 4

Maximum (- 1, 18), Minimum (9, - 482)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x - 27

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = - 1

into

x^{3} - 12 x^{2} - 27 x + 4 : 18

Maximum (- 1, 18)

Plug

x = 9

into

x^{3} - 12 x^{2} - 27 x + 4 : - 482

Minimum (9, - 482)

Maximum (- 1, 18), Minimum (9, - 482)

4 x + 3 y = - 6

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f (x) = ∣ 3 x - 5 ∣ + 1

f (x) = e^{14 x - 15}

f (x) = \frac{x + 7}{x - 3}

What is the extreme f(x)=x^3-12x^2-27x+4 ?
The extreme f(x)=x^3-12x^2-27x+4 is Maximum(-1,18),Minimum(9,-482)