What is the asymptotes of y=(x^2+9)/(9x^2-26x-3) ?

The asymptotes of y=(x^2+9)/(9x^2-26x-3) is Vertical: x=-1/9 ,x=3,Horizontal: y= 1/9

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asymptotes of y=(x^2+9)/(9x^2-26x-3)

asymptotes

y = \frac{x ^{2} + 9}{9 x ^{2} - 26 x - 3}

Vertical : x = - \frac{1}{9}, x = 3, Horizontal : y = \frac{1}{9}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 9}{9 x ^{2} - 26 x - 3} : x = - \frac{1}{9}, x = 3

Horizontal Asymptotes of

\frac{x ^{2} + 9}{9 x ^{2} - 26 x - 3} : y = \frac{1}{9}

Slant Asymptotes of

\frac{x ^{2} + 9}{9 x ^{2} - 26 x - 3} :

None

Vertical : x = - \frac{1}{9}, x = 3, Horizontal : y = \frac{1}{9}

f (x) = x^{2} + 6 x + 4

f (x) = \frac{3 x ^{2}}{x ^{2} + 2}

f (x) = x + 9

y = 10 x^{2}

f (x) = cos (x - \frac{π}{2})

What is the asymptotes of y=(x^2+9)/(9x^2-26x-3) ?
The asymptotes of y=(x^2+9)/(9x^2-26x-3) is Vertical: x=-1/9 ,x=3,Horizontal: y= 1/9