What is the asymptotes of f(x)=(x^2+1)/(x+1) ?

The asymptotes of f(x)=(x^2+1)/(x+1) is Vertical: x=-1,Slant: y=x-1

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asymptotes of f(x)=(x^2+1)/(x+1)

asymptotes

f (x) = \frac{x ^{2} + 1}{x + 1}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

x^{3} - x^{2} - 5 x + 7

f (x) = x^{3} - 6 x^{2} - 15 x + 8

f (x) = 3 x^{4} - 6 x^{2} + 7

- 2 x + y = 1

\frac{2 x + 4}{7}

What is the asymptotes of f(x)=(x^2+1)/(x+1) ?
The asymptotes of f(x)=(x^2+1)/(x+1) is Vertical: x=-1,Slant: y=x-1