What is the domain of f(x)= 9/(sqrt(x)) ?

The domain of f(x)= 9/(sqrt(x)) is x>0

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domain of f(x)= 9/(sqrt(x))

domain

f (x) = \frac{9}{x}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = (x + 1)^{2} (x - 4)^{3}

f (x) = 8 x^{4} - 48 x^{2}

f (x) = \frac{1}{x + 1}

r (x) = \frac{6 x ^{3} - 2}{2 x ^{3} + 5 x ^{2} + 6 x}

(3, - 2), (- 4, 5)

What is the domain of f(x)= 9/(sqrt(x)) ?
The domain of f(x)= 9/(sqrt(x)) is x>0