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Popular >

distance (3,-2),(-4,5)

Solution

distance

(3, - 2), (- 4, 5)

Solution

72

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(3, - 2)

and

(- 4, 5)

is

= (- 4 - 3)^{2} + (5 - (- 2))^{2}

Simplify

= 72

Popular Examples

range of f(x)=5x^2+9 range

f (x) = 5 x^{2} + 9

domain of f(x)=(sqrt(x-1))/(x-4)domain

f (x) = \frac{x - 1}{x - 4}

inverse of f(x)= 1/2 e^{x+3}-4 inverse

f (x) = \frac{1}{2} e^{x + 3} - 4

domain of f(x)=3x(x+3)(x-5)domain

f (x) = 3 x (x + 3) (x - 5)

periodicity of 2sin((2piθ)/3)periodicity

2 sin (\frac{2 π θ}{3})

Frequently Asked Questions (FAQ)

What is the distance (3,-2),(-4,5) ?
The distance (3,-2),(-4,5) is 7sqrt(2)