What is the inverse of f(x)=(x^4+3)/(x^4) ?

The inverse of f(x)=(x^4+3)/(x^4) is \sqrt[4]{3/(x-1)},-\sqrt[4]{3/(x-1)}

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inverse of f(x)=(x^4+3)/(x^4)

inverse

f (x) = \frac{x ^{4} + 3}{x ^{4}}

Solution steps

y = \frac{x ^{4} + 3}{x ^{4}}

Replace

x

with

y

x = \frac{y ^{4} + 3}{y ^{4}}

Solve for

y, x = \frac{y ^{4} + 3}{y ^{4}}

\frac{3 x}{8 x - 3}

- 5 x - 4 y = - 8

sin (2.8 x + 0.9) + 0.3

f (x) = \frac{1}{x - 2}

y = - 3 x

What is the inverse of f(x)=(x^4+3)/(x^4) ?
The inverse of f(x)=(x^4+3)/(x^4) is \sqrt[4]{3/(x-1)},-\sqrt[4]{3/(x-1)}