What is the inverse of f(x)=7x^2+3 ?

The inverse of f(x)=7x^2+3 is sqrt((x-3)/7),-sqrt((x-3)/7)

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inverse of f(x)=7x^2+3

inverse

f (x) = 7 x^{2} + 3

\frac{x - 3}{7}, - \frac{x - 3}{7}

Solution steps

y = 7 x^{2} + 3

Replace

x

with

y

x = 7 y^{2} + 3

Solve for

y, x = 7 y^{2} + 3

\frac{x - 3}{7}, - \frac{x - 3}{7}

5 x - 2 y - 7 = 0, (- 1, 6)

x^{3} - 4

y = \frac{1}{4} x + \frac{9}{4}

f (x) = \frac{( x - 5 )}{2 x + 1}

f (x) = 2 x^{3} + 7 x^{2} + 4 x - 5

What is the inverse of f(x)=7x^2+3 ?
The inverse of f(x)=7x^2+3 is sqrt((x-3)/7),-sqrt((x-3)/7)