What is the perpendicular 3x+4y=0 ?

The perpendicular 3x+4y=0 is y= 4/3 x+b

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perpendicular 3x+4y=0

perpendicular

3 x + 4 y = 0

y = \frac{4}{3} x + b

Solution steps

Find the slope of

3 x + 4 y = 0 : m = - \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = \frac{4}{3}

Line with slope m=

\frac{4}{3} : y = \frac{4}{3} x + b

y = \frac{4}{3} x + b

f (x) = \frac{- 2 x + 13}{- 4 x - 2}

x^{3} + 5

f (x) = \frac{1}{4} x^{3} - 2

3 cos (4 x)

y = 1 - \frac{x}{5}