What is the domain of f(x)=(15)/(x^2+5x) ?

The domain of f(x)=(15)/(x^2+5x) is x 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(15)/(x^2+5x)

domain

f (x) = \frac{15}{x ^{2} + 5 x}

x < - 5 or - 5 < x < 0 or x > 0

Interval Notation

(- \infty, - 5) \cup (- 5, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 5

The function domain

x < - 5 or - 5 < x < 0 or x > 0

f (x) = \frac{x ^{5} - 1}{3 x ^{2} - 2 x - 1}

g (x) = 3 x - 1 + 5

f (x) = - 6 x + 24

f (x) = 3 x^{2} + x - 5

f (x) = - 4 - x^{2}

What is the domain of f(x)=(15)/(x^2+5x) ?
The domain of f(x)=(15)/(x^2+5x) is x<-5\lor-5<x<0\lor x>0