What is the inverse of f(x)= 1/2 (x+3)^2-2 ?

The inverse of f(x)= 1/2 (x+3)^2-2 is sqrt(2x+4)-3,-sqrt(2x+4)-3

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inverse of f(x)= 1/2 (x+3)^2-2

inverse

f (x) = \frac{1}{2} (x + 3)^{2} - 2

2 x + 4 - 3, - 2 x + 4 - 3

Solution steps

y = \frac{1}{2} (x + 3)^{2} - 2

Replace

x

with

y

x = \frac{1}{2} (y + 3)^{2} - 2

Solve for

y, x = \frac{1}{2} (y + 3)^{2} - 2

2 x + 4 - 3, - 2 x + 4 - 3

f (x) = 4 x^{5} - x^{4} + 8 x - 9

f (x) = x^{2} - 4 x - 3, x \leq 2

f (x) = \frac{4 x ^{2} - x}{x ^{2} - 1}

f (x) = - 2^{x}

\frac{x}{1 + x}

What is the inverse of f(x)= 1/2 (x+3)^2-2 ?
The inverse of f(x)= 1/2 (x+3)^2-2 is sqrt(2x+4)-3,-sqrt(2x+4)-3