What is the monotone (6x)/7 (4x)/3 ?

The monotone (6x)/7 (4x)/3 is Decreasing:-infinity <x<0,Increasing:0<x<infinity

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monotone (6x)/7 (4x)/3

monotone intervals

\frac{6 x}{7} \frac{4 x}{3}

Decreasing : - \infty < x < 0, Increasing : 0 < x < \infty

Solution steps

f^{'} (x) = \frac{16 x}{7}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Decreasing : - \infty < x < 0, Increasing : 0 < x < \infty

(2019, - 560631), (2020, 5523594)

\frac{x ^{2} + 1}{2}

\frac{x ^{2} + 7 x}{5 x ^{2} - 1}

f (x) = - \frac{1}{2} x^{2} + 4 x - 2

f (x) = \frac{5}{( x - 2 ) ^{2}}

What is the monotone (6x)/7 (4x)/3 ?
The monotone (6x)/7 (4x)/3 is Decreasing:-infinity <x<0,Increasing:0<x<infinity