What is the domain of f(x)=sqrt((7x^2-63)/9) ?

The domain of f(x)=sqrt((7x^2-63)/9) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((7x^2-63)/9)

domain

f (x) = \frac{7 x ^{2} - 63}{9}

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

- 3 x^{4} - 2 x^{2} + 1

(2, - 3), (- 4, 6)

f (x) = (4 - x) (x^{2} - 1)

f (x) = \frac{x + 5}{x ^{2} + 3}

f (x) = x - \frac{2}{x}

What is the domain of f(x)=sqrt((7x^2-63)/9) ?
The domain of f(x)=sqrt((7x^2-63)/9) is x<=-3\lor x>= 3