What is the inverse of f(x)= 9/(x^2) ?

The inverse of f(x)= 9/(x^2) is (3sqrt(x))/x ,-(3sqrt(x))/x

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inverse of f(x)= 9/(x^2)

inverse

f (x) = \frac{9}{x ^{2}}

\frac{3 x}{x}, - \frac{3 x}{x}

Solution steps

y = \frac{9}{x ^{2}}

Replace

x

with

y

x = \frac{9}{y ^{2}}

Solve for

y, x = \frac{9}{y ^{2}}

\frac{3 x}{x}, - \frac{3 x}{x}

f (x) = x^{4} + 4 x^{3} + 7

8 x

f (x) = 2 + 5 x - x^{2}

y = x^{2} - 1

\frac{1}{x + 2}

What is the inverse of f(x)= 9/(x^2) ?
The inverse of f(x)= 9/(x^2) is (3sqrt(x))/x ,-(3sqrt(x))/x