What is the asymptotes of f(x)=(x^2-3x)/(2x^2+2x-12) ?

The asymptotes of f(x)=(x^2-3x)/(2x^2+2x-12) is Vertical: x=-3,x=2,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2-3x)/(2x^2+2x-12)

asymptotes

f (x) = \frac{x ^{2} - 3 x}{2 x ^{2} + 2 x - 12}

Vertical : x = - 3, x = 2, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x}{2 x ^{2} + 2 x - 12} : x = - 3, x = 2

Horizontal Asymptotes of

\frac{x ^{2} - 3 x}{2 x ^{2} + 2 x - 12} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 3 x}{2 x ^{2} + 2 x - 12} :

None

Vertical : x = - 3, x = 2, Horizontal : y = \frac{1}{2}

\frac{x}{1 + x ^{2}}

(- 4, 1), (1, 5)

\frac{2}{x ^{2}} + ln (x)

What is the asymptotes of f(x)=(x^2-3x)/(2x^2+2x-12) ?
The asymptotes of f(x)=(x^2-3x)/(2x^2+2x-12) is Vertical: x=-3,x=2,Horizontal: y= 1/2