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Popular >

extreme f(x)=x^2+14x+33

Solution

extreme points

f (x) = x^{2} + 14 x + 33

Solution

Minimum (- 7, - 16)

Solution steps

f^{'} (x) = 2 x + 14

Find intervals:

Decreasing

: - \infty < x < - 7,

Increasing

: - 7 < x < \infty

Plug

x = - 7

into

x^{2} + 14 x + 33 : - 16

Minimum (- 7, - 16)

Popular Examples

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domain of (x^2-2x-15)/(x^2+4x)domain

\frac{x ^{2} - 2 x - 15}{x ^{2} + 4 x}

inverse of f(x)=7x^2-8 inverse

f (x) = 7 x^{2} - 8

slope ofintercept 20x-40y=160 slope intercept

20 x - 40 y = 160

perpendicular y=-3/4 x-6 perpendicular

y = - \frac{3}{4} x - 6

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+14x+33 ?
The extreme f(x)=x^2+14x+33 is Minimum(-7,-16)