What is the critical (x^2-9)^6 ?

The critical (x^2-9)^6 is x=-3,x=0,x=3

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critical (x^2-9)^6

critical points

(x^{2} - 9)^{6}

x = - 3, x = 0, x = 3

Solution steps

(x^{2} - 9)^{6}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 0, x = 3

Identify critical points not in

f (x)

domain

Domain of

(x^{2} - 9)^{6} : - \infty < x < \infty

All critical points are in domain

x = - 3, x = 0, x = 3

4 - x^{2}

f (x) = \frac{x + 1}{x - 1}

(- 1, 5), (- 5, 5)

f (x) = \frac{5}{2 x ^{2} + 1}

(5, - 4), (- 1, - 4)