What is the inverse of f(x)=\sqrt[3]{4x-9} ?

The inverse of f(x)=\sqrt[3]{4x-9} is (x^3+9)/4

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inverse of f(x)=\sqrt[3]{4x-9}

inverse

\frac{x ^{3} + 9}{4}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} + 9}{4}

3 x + 4 y = 4

f (x) = x^{4} + 6 x^{3} - x - 6

f (x) = \frac{4 x - 8}{6 - 5 x}

y = x^{2} - x

f (x) = 6 x^{3} - 9 x^{2} - 36 x

What is the inverse of f(x)=\sqrt[3]{4x-9} ?
The inverse of f(x)=\sqrt[3]{4x-9} is (x^3+9)/4