What is the shift f(x)=8cos(pi^2x-pi^4)-3 ?

The shift f(x)=8cos(pi^2x-pi^4)-3 is Phase:pi^2, Vertical:-3

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shift f(x)=8cos(pi^2x-pi^4)-3

shift

f (x) = 8 cos (π^{2} x - π^{4}) - 3

Phase : π^{2}, Vertical : - 3

Solution steps

f (x) = 8 cos (π^{2} x - π^{4}) - 3

g (B x - C) = cos (π^{2} x - π^{4}), B = π^{2}, C = π^{4}, D = - 3

Therefore, the phase shift

\frac{C}{B}

\frac{π ^{4}}{π ^{2}}

π^{2}

The vertical shift

D

- 3

- 3

f (x) = 500 (0.04 - x^{2})

(49) (- 4 7)

y - 2 = 0

f (x) = \frac{3 x + 2}{2 x + 5}

d x

What is the shift f(x)=8cos(pi^2x-pi^4)-3 ?
The shift f(x)=8cos(pi^2x-pi^4)-3 is Phase:pi^2, Vertical:-3