What is the domain of f(x)=sqrt(36-9x^2) ?

The domain of f(x)=sqrt(36-9x^2) is -2<= x<= 2

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domain of f(x)=sqrt(36-9x^2)

domain

f (x) = 36 - 9 x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

(- 3, - 6), (1, 4)

- 2 x^{2} + 2 x - 4

3 x^{2} - 14 x + 15

(x - 4)^{2} = 24 (y + 3)

f (x) = \frac{6}{3 - x}

What is the domain of f(x)=sqrt(36-9x^2) ?
The domain of f(x)=sqrt(36-9x^2) is -2<= x<= 2