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Popular >

range of-2x^2+2x-4

Solution

range

- 2 x^{2} + 2 x - 4

Solution

f (x) \leq - \frac{7}{2}

+1

Interval Notation

(- \infty, - \frac{7}{2}]

Solution steps

Vertex of

- 2 x^{2} + 2 x - 4 :

Maximum

(\frac{1}{2}, - \frac{7}{2})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 2,

Vertex

(x_{v}, y_{v}) = (\frac{1}{2}, - \frac{7}{2})

f (x) \leq - \frac{7}{2}

Popular Examples

intercepts of 3x^2-14x+15 intercepts

3 x^{2} - 14 x + 15

symmetry (x-4)^2=24(y+3)symmetry

(x - 4)^{2} = 24 (y + 3)

inverse of f(x)= 6/(3-x)inverse

f (x) = \frac{6}{3 - x}

inverse of f(x)=(x-1)/(x+4)inverse

f (x) = \frac{x - 1}{x + 4}

domain of f(x)=(x^2)/(4x-5)domain

f (x) = \frac{x ^{2}}{4 x - 5}

Frequently Asked Questions (FAQ)

What is the range of-2x^2+2x-4 ?
The range of-2x^2+2x-4 is f(x)<=-7/2