What is the domain of f(x)=(x^2)/(4x-5) ?

The domain of f(x)=(x^2)/(4x-5) is x 5/4

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domain of f(x)=(x^2)/(4x-5)

domain

f (x) = \frac{x ^{2}}{4 x - 5}

x < \frac{5}{4} or x > \frac{5}{4}

Interval Notation

(- \infty, \frac{5}{4}) \cup (\frac{5}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{4}

The function domain

x < \frac{5}{4} or x > \frac{5}{4}

f (x) = 2 x + 3 = 0

f (x) = \frac{1}{2} \cdot 4^{x}

f (x) = \frac{x - 3}{3} + 1

f (x) = \frac{x ^{2} + 4 x - 5}{x ^{2} - 9}

x^{2} - 1 x = 1

What is the domain of f(x)=(x^2)/(4x-5) ?
The domain of f(x)=(x^2)/(4x-5) is x< 5/4 \lor x> 5/4