What is the monotone f(x)=-6x^2+12000x ?

The monotone f(x)=-6x^2+12000x is Increasing:-infinity <x<1000,Decreasing:1000<x<infinity

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monotone f(x)=-6x^2+12000x

monotone intervals

f (x) = - 6 x^{2} + 12000 x

Increasing : - \infty < x < 1000, Decreasing : 1000 < x < \infty

Solution steps

f^{'} (x) = - 12 x + 12000

Find intervals:

Increasing

: - \infty < x < 1000,

Decreasing

: 1000 < x < \infty

Increasing : - \infty < x < 1000, Decreasing : 1000 < x < \infty

(x - 5)^{2} - 4

f (x) = \frac{1}{1 + tan ^{2} ( x )}

f (x) = \frac{x - 1}{sin ( 2 x )}

y = \frac{1}{5} x + 5, (8, - 3)

f (x) = 2 x + 12

What is the monotone f(x)=-6x^2+12000x ?
The monotone f(x)=-6x^2+12000x is Increasing:-infinity <x<1000,Decreasing:1000<x<infinity