What is the range of f(x)=(x+1)/(x-2) ?

The range of f(x)=(x+1)/(x-2) is f(x) 1

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range of f(x)=(x+1)/(x-2)

range

f (x) = \frac{x + 1}{x - 2}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 1}{x - 2}

Inverse of

\frac{x + 1}{x - 2} : \frac{1 + 2 x}{x - 1}

\frac{1 + 2 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{1 + 2 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

f (x) = \frac{1}{x + 2} + 4

f (x) = \frac{x + 8}{x ^{2} - 64}

\frac{2 x}{x + 5}

(4, 14), (16, 4)

4 - x^{2}

What is the range of f(x)=(x+1)/(x-2) ?
The range of f(x)=(x+1)/(x-2) is f(x)<1\lor f(x)>1