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Popular >

f(x)=sqrt(x^2+2x-8)

Solution

f (x) = x^{2} + 2 x - 8

Solution

Domain : x \leq - 4 or x \geq 2

Range : f (x) \geq 0

X Intercepts : (2, 0), (- 4, 0)

Asymptotes : Slant y = x + 1, y = - x - 1

Extreme Points : Minimum (- 4, 0), Minimum (2, 0)

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Solution steps

Domain of

x^{2} + 2 x - 8 : x \leq - 4 or x \geq 2

Range of

x^{2} + 2 x - 8 : f (x) \geq 0

Axis interception points of

x^{2} + 2 x - 8 :

X Intercepts

: (2, 0), (- 4, 0)

Asymptotes of

x^{2} + 2 x - 8 :

Slant

: y = x + 1, y = - x - 1

Extreme Points of

x^{2} + 2 x - 8 :

Minimum

(- 4, 0),

Minimum

(2, 0)

Popular Examples

f(x)= 1/(x^2-2x-3)

f (x) = \frac{1}{x ^{2} - 2 x - 3}

f (x) = 5 x^{3} - 4

f(x)= 1/(x^2-2x+1)

f (x) = \frac{1}{x ^{2} - 2 x + 1}

f(x)=-2(x+4)^2+3

f (x) = - 2 (x + 4)^{2} + 3

y = 5 x + 14

Frequently Asked Questions (FAQ)

What is the f(x)=sqrt(x^2+2x-8) ?
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