What is the domain of f(x)=3+(4+x)^{1/2} ?

The domain of f(x)=3+(4+x)^{1/2} is x>=-4

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domain of f(x)=3+(4+x)^{1/2}

domain

f (x) = 3 + (4 + x)^{\frac{1}{2}}

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

f (x) = \frac{x + 3}{( 2 x + 3 ) ( x - 1 )}

f (x) = \frac{2}{x + 1} + 3

- 2 x^{2} - 2 x - 2

- x^{4} - 2 x^{3} + 2 x^{2} - 5

f (x) = \frac{8 + 5 x}{x - 1}

What is the domain of f(x)=3+(4+x)^{1/2} ?
The domain of f(x)=3+(4+x)^{1/2} is x>=-4