What is the inverse of f(x)=2x^2+16x+29 ?

The inverse of f(x)=2x^2+16x+29 is (-16+sqrt(8x+24))/4 ,(-16-sqrt(8x+24))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2x^2+16x+29

inverse

f (x) = 2 x^{2} + 16 x + 29

\frac{- 16 + 8 x + 24}{4}, \frac{- 16 - 8 x + 24}{4}

Solution steps

y = 2 x^{2} + 16 x + 29

Replace

x

with

y

x = 2 y^{2} + 16 y + 29

Solve for

y, x = 2 y^{2} + 16 y + 29

\frac{- 16 + 8 x + 24}{4}, \frac{- 16 - 8 x + 24}{4}

\frac{x}{x - 1}

f (x) = 2 x^{2} + 24 x + 76, - 6 \leq x \leq 2

\frac{3 x - 5}{4 x + 13}

f (x) = \frac{2 x + 5}{3}

f (x) = 1 - 3 x

What is the inverse of f(x)=2x^2+16x+29 ?
The inverse of f(x)=2x^2+16x+29 is (-16+sqrt(8x+24))/4 ,(-16-sqrt(8x+24))/4